36x^2+12x=80

Solution for 36x^2+12x=80 equation:

36x^2+12x=80

We move all terms to the left:

36x^2+12x-(80)=0

a = 36; b = 12; c = -80;
Δ = b2-4ac
Δ = 122-4·36·(-80)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-108}{2*36}=\frac{-120}{72}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+108}{2*36}=\frac{96}{72}
=1+1/3
$